36x^2-42+12=0

Solution for 36x^2-42+12=0 equation:

36x^2-42+12=0

We add all the numbers together, and all the variables

36x^2-30=0

a = 36; b = 0; c = -30;
Δ = b2-4ac
Δ = 02-4·36·(-30)
Δ = 4320
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4320}=\sqrt{144*30}=\sqrt{144}*\sqrt{30}=12\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{30}}{2*36}=\frac{0-12\sqrt{30}}{72}
=-\frac{12\sqrt{30}}{72}
=-\frac{\sqrt{30}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{30}}{2*36}=\frac{0+12\sqrt{30}}{72}
=\frac{12\sqrt{30}}{72}
=\frac{\sqrt{30}}{6}
$